Несоответствие контрольной суммы MX Linux ISO

Пробовал с помощью команд, указанных ниже, тоже работает нормально

Step1

awk 'NR==FNR{a[$5];next}($1 in a){print $0}' file1 file2 > u.txt
count=`awk '{print NR}' u.txt | sort -nr| sed -n '1p'`

step2

for ((i=1;i<=$count;i++)); do h=`awk -v i="$i" 'NR==i{print $1}' u.txt`; j=`awk -v i="$i" 'NR==i{print $2}' u.txt `; awk -v h="$h" -v j="$j" '$5 == h {$6=j;print $0}' file1; done >file3.txt


step3

awk 'NR==FNR{a[$1];next}!($5 in a){print $0}' file2 file1 >file4.txt


Step4(Final output)

awk '{print $0}' file3.txt file4.txt
-. ID = tom_fa_10005086 ABI3VP1
- 0 Parent = tom_fa_10005086 ABI3VP1
- 0 Parent = tom_fa_10005086 ABI3VP1
- 2 Parent = tom_fa_10005086 ABI3VP1
- 1 Parent = tom_fa_10005086 ABI3VP1
- 0 Parent = tom_fa_10005086 ABI3VP1
- 0 Parent = tom_fa_10005086 ABI3VP1
+. ID = tom_fa_10013928 ABI3VP2
+ 0 Parent = tom_fa_10013928 ABI3VP2
+ 0 Parent = tom_fa_10013928 ABI3VP2
+ 0 Parent = tom_fa_10013928 ABI3VP2
+ 0 Parent = tom_fa_10013928 ABI3VP2
+ 2 Parent = tom_fa_10013928 ABI3VP2
+ 2 Parent = tom_fa_10013928 ABI3VP2
+ 1 Parent = tom_fa_10013928 ABI3VP2
+ 1 Parent = tom_fa_10013928 ABI3VP2
+ 2 Parent = tom_fa_10013928 ABI3VP2
+ 2 Parent = tom_fa_10013928 ABI3VP2
-. ID = tom_fa_10000024 Alfin-like
- 0 Parent = tom_fa_10000024 Alfin-like
-  .   ID  =   tom_fa_10004587
-   0   Parent  =   tom_fa_10004587
-   1   Parent  =   tom_fa_10004587
-   1   Parent  =   tom_fa_10004587
+  .   ID  =   tom_fa_10018753
+   0   Parent  =   tom_fa_10018753
+   2   Parent  =   tom_fa_10018753
+   2   Parent  =   tom_fa_10018753
+   0   Parent  =   tom_fa_10018753
+  .   ID  =   tom_fa_10007441
+   0   Parent  =   tom_fa_10007441
+   0   Parent  =   tom_fa_10007441
+   1   Parent  =   tom_fa_10007441
+   0   Parent  =   tom_fa_10007441
+   1   Parent  =   tom_fa_10007441
+   2   Parent  =   tom_fa_10007441