Можно ли передать аргумент через команду «псевдоним»? [дубликат]

Исправленный оригинал

#!bin/sh
a=0
while [ "$a" -lt "50" ] # mind the spaces and double quote the variable
do
echo "$a"
a=`expr $a + 1` # replace single quotes with backticks, mind the space between $a and 1
done

Улучшения

#!bin/bash  # Why not put bash here? sh may not always be linked to bash
a=0
while [ "$a" -lt "50" ] # mind the spaces and double quote the variable
do
echo "$a"
a=$(expr $a + 1) # replace legacy backticks with $()
# Or better you can even use double parenthesis which allows you do
# (( a++ )) , note the C style increment operator here
done

^{Примечание Для проверки скриптов используйте [shellcheck] .}