Bash stdout и/или stderr history log [duplicate]

Awksolución:

awk -F',' 'function reformat_date(c){     # `c` - column value as an argument
               y = substr(c, 7, 4);       # extract `year` value
               sub(/\/[0-9]{4}/, "", c);  # remove `year` value
               return y"/"c               # return rearranged `YYYY/MM/DD` value
           }
           { $8 = reformat_date($8); $9 = reformat_date($9) }1' OFS=',' file.csv

Muestra de salida:

1111,2222,3333,4444,5555,6666,7777,2017/11/27 18:58:48,2017/11/27 19:07:57