Преобразование вывода даты по умолчанию в эпоху Unix

в опубликованном make-файле отсутствуют некоторые детали

Примечание: (почти) всегда лучше отделить этап компиляции от этапа связывания

следующий make-файл исправляет эти детали

Примечание: означает использование клавиши табуляции в самом make-файле.

RM             := /usr/bin/rm

LFLAGS         += `pkg-config wayland-client --libs`

CFLAGS         := -std=c11 -Wall -Werror -O3 -fvisibility=hidden
CFLAGS         += `pkg-config wayland-client --cflags`

OBJS           := hello_wayland.o helpers.o
HDRS           := helpers.h

TARGET         := hello_wayland

.PHONY: all
all: $(TARGET)

$(TARGET): $(OBJS) images.bin
<tab>$(CC) -o hello_wayland *.o $(LFLAGS) -lrt

%.o:%.c $(HDRS)
<tab>$(CC) $(CFLAGS)-c $< -o $@ -I.

images.bin: images/convert.py images/window.png images/fish.png
<tab>images/convert.py
<tab>cat window.bin fish.bin > images.bin

.PHONY: clean
clean:
<tab>$(RM) *.o fish.bin window.bin hello_wayland

Вы спрашиваете, что не так с исходным make-файлом:

вот некоторые наблюдения:

-- macros in a make file are of two types:
   those evaluated only once using `:=`
   those evaluated every time they are referenced `=`

WAYLAND=`pkg-config wayland-client --cflags --libs`
== WAYLAND will be re-evaluated every time referenced

CFLAGS?=-std=c11 -Wall -Werror -O3 -fvisibility=hidden
== invalid format for macro.  `?=` should be `:=`

== in a makefile,  typical usage is `make all`  but this makefile is missing that target (which should be the first target so `make` by itself, will execute the first target)
== `targets` for a link step should not be the actual file name
==== but rather a macro name where that macro contains the target name
==== This usage of a macro also makes it easy to set the resulting executable file name at the invocation of `make`
==== while either way will work, for flexability it is best to create a macro
==== this is expecially true when writing a recursive makefile or multiple different executables
hello_wayland: hello_wayland.o helpers.o helpers.h images.bin

== this is a link step, with hidden compiles, using the default recipe, which knows nothing about any specific header file
==== so the hidden compiles will not be done if the header file changes
== and a header file `helpers.h` should never be in a link step
== the `*.o` is a `glob` operation, which should not be used in makefiles
==== instead use the make facilties:

SRC := $(wildcard *.c)
OBJ := $(SRC:.c=.o)

== the 'target' is properly referenced by `$@` and there can be no keypunch errors if the `$@` is used.
    $(CC) -o hello_wayland *.o $(WAYLAND) -lrt

images.bin: images/convert.py images/window.png images/fish.png
    images/convert.py
    cat window.bin fish.bin > images.bin

== when a `target` is not the name of a produced file,
==== especially in older versions of `make`
==== then the target needs to be preceeded by a 

.PHONY: <list of target names that produce no actual output file>

== using  a `glob` operation in a makefile is a bad idea
==== instead use the appropriate macro
==== like the $(OBJS) macro listed above
clean:
    $(RM) *.o fish.bin window.bin hello_wayland

Итак, почему исходный make-файл не работал? комбинация вещей, которые накапливаются в отказе. Вот более очевидные причины:

1) the incorrect setting of the CFLAGS macro
2) the combining of the link operation with the compile operations
3) the missing .PHONY: statement
4) the use of the `glob` statements